Question

Please help @shubhamsrg

Answer 1

LOL..

Answer 2

ok so one minute let me think

Answer 3

^_^

Answer 4

for these type of ques,,what i usually do/did during practicing was took n to be something,,lets say 0 so that n+1 = 1 ,,or maybe 1 for n+1 =2
you may try now and go for option checking..

Answer 5

k:)
but isn't there a logical way?

Answer 6

must be,,i'll get back to it..

Answer 7

ok.

Answer 8

\[\huge{\frac{2n+1}{2n-1}}\]

Answer 9

answer is \[\frac{2n-1}{2n+1}\]

Answer 10

k let me check this again

Answer 11

ok:)

Answer 12

you know dist for nth second?
its asking for that..

Answer 13

Oh yes u r right

Answer 14

i have to go very sorry :
http://www.tekoclasses.com/IITJEE%20PHYSICS%20ENGLISH/KINEMATICS%20TYPE%201.pdf

u can prefer this

Answer 15

ya \[S_n=u+\frac{1}{2}a{(2t-1)}\]

Answer 16

k i gt now:)

Answer 17

hmm..

Answer 18

?

Answer 19

this is the formula used

Answer 20

oops sorry my bad.

Answer 21

i mean great that you got it..it uses the very same formulla,,taking v0 =0

Answer 22

so thanx to both fr help:)

Answer 23

very easy question lol
yet i took it hard:/