Question

2 / 6 - √3

Answer 1

@MarieePR does the expression look like this :
\[\frac{2}{6-\sqrt3}\]

or
\[\frac{2}{6}-\sqrt3\]

?

Answer 2

the first one

Answer 3

ok.. these problems we must start with rationalizing the denominator.
by multiplying with unity values.

by multiplying with \(\huge \frac{6+\sqrt3}{6+\sqrt3}\) ,it becomes :

\(\huge \frac{2}{6-\sqrt3} *\frac{6+\sqrt3}{6+\sqrt3}\)

\(\huge = \frac{12 + 2\sqrt3}{6^2-\sqrt3^2}\)


\(\huge = \frac{12 + 2\sqrt3}{33}\)