Find the solution of the inequality. |x-5|greater than or equal to 3
So geometrically, it's all numbers x which are a distance of 3 or more from 5. What numbers are those?
no its this sign > with a line under it so thats why i put greater than or equal to
Yes, so at a distance 3 or more from 5. For example 8 and all numbers greater than 8. Hence one part of the solution is the real numbers \( x \) such that \( x \geq 8 \). Now, what's the other part?
I have no clue I don't understand this whole question at all
Let's step back. What is the definition of |x|?
?
What does |x| mean?
um again i don't know
Ok. |x| is called the absolute value of x. It measures how far the number x is from zero on the real number line. How far is 1 from 0? 1. Hence |1| = 1. How far is -1 from 0? 1. Hence |-1| = 1. How far is 0 from 0? 0. Hence |0| = 0. Now what is |2| and |-2| ?
0?
No, 2 is a distance of 2 units away from zero. Hence |2| = 2. What then is |-2| = ?
2
Yes. Now what is |-5|?
5
Yes. And what is |2-1|? This is the distance between 2 and 1
1?
Yes. And what is the distance between 1 and -1? |1-(-1)| = ... ?
0?
Is 1 = -1? I don't think so. Try again. |1-(-1)| = ... ?
1
Draw a number lilne. Locate -1 and locate +1. How far apart are they?
well its -1 then 0 then 1
Yes, so they are a distance of 2 apart. I.e., |1-(-1)| = |1+1| = 2.
ohhh ok
Now, what number or numbers x are a distance 2 apart from 1? i.e., |x-1| = 2.
1?
How far apart is 1 from 1? A distance of zero. Hence if x=1, then |x-1| = 0. We want numbers x such that |x-1| = 2. What's one number x that is a distance 2 away from 1?
look at a number line.
ughhh i just don't understand this
Draw a number line. Mark 0 and 1 and the numbers -5 to 5 on it. Now look at 1. What are the numbers a distance 2 to the left of 1 and 2 to the right of 1?
x is less than or equal to 8 or x is greater than or equal to 2 this is what I put on my test
We're coming back to your problem next. But answer this one first. If x is a real number with the property that |x-1| = 2 i.e., x is a distance of 2 away from +1, what values can x have?
-1 and 3?
3 is one such number. 3 is a distance 2 away from +1. This makes sense as |3-1| = |2| = 2. Now, what's the other number x such that |x-1| = 2 ?
Yes -1 and 3.
returning now to your problem, we are told that \[ |x-5| \geq 3 \] Let's first solve \[ | x - 5| = 3 \] What two numbers satisfy this last equation?
i.e., x is a distance 3 from +5.
so that would be 2?
That's one number. What's the other?
-2?
No. the difference between -2 and 5 is 7. I.e., |(-2)-5| = |-7| = 7. Try again. |x-5| = 3
is it 8
Yes of course. 8 and 2 are both a distance 3 from 5. i.e., if |x-5| = 3, then x = 3 or 8.
Now you want real numbers x such that \[ |x-5| \geq 3 \] So the distance is equal to or \( \it greater \) than 3. What's a number more than 3 away from 5?
4
9 is one such number. So is 10 and 11 and 20 and 200 and 2000 and 50000 and 100000. So is 8.5 and 8.1 and 8.00001 and 8.0000000001.
Hence *every* number greater than 8 is more than a distance of 3 away from 5.
so 9?
Look at the number line. *EVERY* number greater than 8 is more than a distance 3 away from 5. Hence EVERY number greater than or equal to 8 satisfies \[ |x-5| \geq 3 \] make sense?
kinda
im working on it might be getting there but slowly lol
Now, look on the other side of 5. What are the numbers x which are a distance of 3 or more from 5?
We know that 2 is one of them. What other numbers?
8?
is that a question or statement?
Draw a number line. Mark on it 0 and 5 and 10 and -5 and -10.
Tell me when you've done that.
In fact, mark on it all the numbers from -10 to 10.
k hold on
ok i got it
ok. Now look at 5. What numbers are 3 or more away from 5. Well, on the right hand side, clearly 8 is at least a distance 3 away from 5. And in fact, so must every number greater than 8. So far so good?
yes
Now, to the left of 5, what number is *exactly* a distance of 3 away from 5?
2?
Yes 2. Now staying to the left of 5, what numbers are a distance of more than 3 away from 5?
uhh.. going 3 distance away from would be 2 or if your asking to go 3 more away from five would be -1
I am asking for numbers to the left of 5 on the number line, in other words for numbers less than 5, what is an example of a number which is a distance of more than 3 away from 5?
For example, 1 is at a distance of 4 from 5. Hence x=1 satisfies \[ |x-5| \geq 3 \] Yes?
so it would be 4?
because in fact |1-5| = |-4| = 4. That is, the distance between 5 and 1 is 4. Now what are all the numbers less than 5 which are at a distance of more than 3? Look at the number line. You know that 2 is *exactly* 3 from 5. What numbers are more than a distance of 3 from 5?
3 & 4?
omg im so confused
the distance between 3 and 5 is 2: |3-5| = |-2| = 2 The distance between 4 and 5 is 1: |4-5| = |-1| = 1 So no, that cannot be right.
Again, what numbers are *exactly* a distance of 3 away from 5? 8 and 2. Agreed?
yes, it is and would it be 1?
So if the question was: for what values of x is |x-5| = 3 the answers would be 2 and 8, and we'd be finished. But that's not the problem.
The problem is: For what values of x is \[ |x-5| \geq 3 \] That is, what numbers x are at least a distance of 3 away from 5.
sorry im taking all of your time im just dumb i guess..
Now, clearly 8 is at least 3 away from 5 and hence every number greater than 8 is more than a distance of 3 away from 5. So far so good?
yea
Now what other number is *exactly* a distance of 3 away from 5?
2?
i dont get how there is another number exactly a distance of 3 away from 5
Yes 2. Now what other numbers to the left of 5 are more than 3 units away from 5?
Look at the number line. You have to go 3 units from 5 to 8. And 3 units from 5 to 2. Absolute value measures distance, not direction, not plus/minus. All we care about here is measuring distance.
I don't know what that means. But +1 is more than 3 units away from 5. So is 0, so is -1. So is 1.5, so is 1.9. In fact, every number less than 2 is more than 3 units distance from 5. Make sense?
thats more less what i just said every number away from 2 is more than 3 units away from 5
less than 2, right. So let's pull this altogether: What are all the real numbers x such that \[ |x-5| \geq 3 \]?
2 and 8
No, that's the solution to the question: What are the real numbers x such that \[ |x-5| = 3 \] ?
thats what the question is about finding the solution
Your original question was: "Find the solution of the inequality. |x-5|greater than or equal to 3" So you need the inequalities as well. In other words, you don't want just the x such that \[ |x-5| = 3 \] We also want the x such that \[ |x-5| > 3 \]
In other words, we don't just want the x which are exactly a distance 3 from 5, we also want all the x which are a distance greater than 3 from 5.
ok
would it be |2-5|=3
x=2 is one solution. But it's not all the solutions.
Look at your number line.
We want all of the numbers x which are a distance of 3 or more from 5.
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