Make a two-column proof showing statements and reasons to prove that triangle DEF is similar to triangle DEG.
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OpenStudy (anonymous):
where is the figure
OpenStudy (anonymous):
OpenStudy (anonymous):
here
OpenStudy (anonymous):
tips?
OpenStudy (anonymous):
can you help me with this problem?
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OpenStudy (anonymous):
k
OpenStudy (anonymous):
tips?
OpenStudy (anonymous):
I posted this as my proof
OpenStudy (anonymous):
1. Angle DEG is equal to angle GFE because it is already given.
2. Side EF is seemingly similar to side ED because of the definition of corresponding sides.
3. Side DG is seemingly similar to side GF because of the definition of corresponding sides.
4. EG=EG because of the reflexive property of equality.
5. Since the triangles both have hypotenuses, they must both have right angles because of the Pythagorean theorem.
6. Since angle DEG=GFE, angle FGE=DGE, and EG=EG, it can be safe to say that the triangles are similar by the AAS Postulate.
OpenStudy (anonymous):
is that right?
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OpenStudy (anonymous):
cal?
OpenStudy (anonymous):
Is my proof right?
OpenStudy (anonymous):
Well, you can't really say that they seem to be congruent because that's not a theorem. In addition, you can't sya that they're hypotenuse because there is no right angle.
OpenStudy (anonymous):
well
OpenStudy (anonymous):
then can I do?
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OpenStudy (anonymous):
can you give me some pointers?
OpenStudy (anonymous):
you there, KingGeorge?
OpenStudy (anonymous):
you guys there?
OpenStudy (anonymous):
k
OpenStudy (anonymous):
ehh
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OpenStudy (kinggeorge):
Definitely not correct. However, all you need to show similarity is two angles.
OpenStudy (anonymous):
k
OpenStudy (anonymous):
ehh
OpenStudy (anonymous):
1. Angle DEG is equal to angle GFE because it is already given.
OpenStudy (kinggeorge):
So which two angles can you show are congruent?
^That's one.
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OpenStudy (anonymous):
k
OpenStudy (anonymous):
ehh
OpenStudy (anonymous):
EG=EG reflexive property of equality
OpenStudy (kinggeorge):
We're looking for an angle, not a side.
OpenStudy (anonymous):
so, FGE and DGE
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OpenStudy (anonymous):
right?
OpenStudy (anonymous):
the triangles share that same exact leg
OpenStudy (kinggeorge):
You're looking at the wrong triangles I think. You want \[\Delta DEF, \quad \Delta DEG\]
OpenStudy (anonymous):
wah
OpenStudy (anonymous):
why?
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OpenStudy (anonymous):
ahh
OpenStudy (anonymous):
Here's a hint. You can find this second pair of angles congruent by using the reflexive property.
OpenStudy (anonymous):
so angle GDE and
OpenStudy (kinggeorge):
The big one, and the next biggest one. Because that's what the problem wants...
OpenStudy (anonymous):
angle DFE?
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OpenStudy (kinggeorge):
Use calc's hint. GDE and...
OpenStudy (anonymous):
GDE and GDE?
OpenStudy (anonymous):
GDE and GFE?
OpenStudy (anonymous):
which is it?
OpenStudy (kinggeorge):
Which one can we use the reflexive property on?
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OpenStudy (anonymous):
GDE?
OpenStudy (anonymous):
Just in case you forgot the reflexive property, it's like this AB = AB. Which angle can be like this?
OpenStudy (anonymous):
GDE?
OpenStudy (anonymous):
or GED?
OpenStudy (anonymous):
You had it right the first time. @KingGeorge We can just leave the angle as <D = <D since their's only one angle there for each triangle?
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OpenStudy (anonymous):
GDE!!!!!!!!!!!!!!!!!!!!!!!!!!!!
OpenStudy (anonymous):
k
OpenStudy (anonymous):
So step one
OpenStudy (anonymous):
1. Angle DEG is equal to angle GFE because it is already given.
OpenStudy (anonymous):
2. GDE=GDE by the reflexive property of equality?
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OpenStudy (kinggeorge):
@Calcmathlete yes we can just leave it like that
@luisz correct
OpenStudy (anonymous):
ty KingGeorge
OpenStudy (anonymous):
k
OpenStudy (anonymous):
next problem
OpenStudy (anonymous):
I think you left something out of the answer. You have to have your concluding statement.
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OpenStudy (anonymous):
and reason.
OpenStudy (kinggeorge):
Yup, still need to finish it off. You just have the first couple steps.