Six squash balls are packaged in a cylindrical container. Calculate the volume of air inside the container.
You can do this for the space around one ball, and then multiply the answer by 6. Then the problem reduces to comparing the volume of a cylinder to one of a sphere, when they have the same diameter (and the height of the cylinder is the diameter of the ball).
Volume of cylinder of radius r: V = pi r^2 h. Volume of cylinder whose height is 2r: V = pi r^2 (2r) = 2 pi r^3. Volume of sphere or radius r: (4/3) pi r^3.
So the answer for one ball is 2 pi r^3 minus (4/3) pi r^3, or (2/3) pi r^3. Multiply this by 6 and you're done.
(And note that above where I wrote "sphere or radius r" the "or" should be "of" -- sorry.)
its ok! Thank you!!
Did you get it? Did I lose you somewhere?
no I got it thank you :)
For one ball it is (2/3) pi r^3. For six it would be six times that, or 4 pi r^3. So the answer is 4 pi r^3, where r is the radius of one ball (or the radius of the container).
yeah I got that answer Thanks a lot! :)
I don't know the radius of a squash ball offhand, sorry!
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