The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions?

Which of the following equations is used in the process of solving this problem?
x2 - 7x + 70 = 0
x2 - 7x + 10 = 0
x2 + 7x - 10 = 0

Question

The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions?

Which of the following equations is used in the process of solving this problem?
x2 - 7x + 70 = 0
x2 - 7x + 10 = 0
x2 + 7x - 10 = 0

ganeshie8 · Answer

let the number be : $x$
square of a number : $x^2$

7 times the number : $7x$
10 less above : $7x-10$

so lets put the equation  : $ x^2 = 7x-10$

now can you subtract or add... and make the RHS 0 ?

anonymous · Answer

x2=10-7x
so making one side of the equation equals to 0; x2 + 7x -10 =0

anonymous · Answer

x^2 - 7x + 10?

ganeshie8 · Answer

correct :)
now you can solve the quadratic equation to get the two possible solutions ! good luck

anonymous · Answer

thanks  :)

ganeshie8 · Answer

welcome (: