Question

http://tinypic.com/r/2005tvk/6

Okay if angles C and A are 45 degrees and side BC is 4.5 sentimeters, can someone tell me if this work (to solve for one of the other side lengths) is correct?

AB = BC tan45 = 4.5cm.
AC = BC/cos(angle C) = 4.5/cos45 = 6.36cm.
4.5/cos45 = 6.36396 cm which rounded to the nearest hundredth is 6.36.

Answer 1

\(BC=4.5\) and so \(AB=4.5\) and therefore the hypotenuse is
\[\sqrt{4.5^2+4.5^2}=\sqrt{2\times 4.5^2}=4.5\sqrt{2}\]

Answer 2

would this be right:

tan(C) = AB/BC
AB = BC*tan(C)
= BC*tan(45 degrees)
= 4.5 cm

Answer 3

which tells you that to get the hypotenuse of an isosceles right triangle multiply the length of the leg by \(\sqrt{2}\)

Answer 4

too much work. if on angle is 45 degrees and one angle is 90 degrees ( a right angle) the the other angle must also be 45 degrees. this tells you the triangle is isosceles and so if one leg is 4.5 so is the other

Answer 5

oh okay, well i'd rather have too much work than too less so just in case.. but that's still correct, right? can i write that instead of what i had before?

Answer 6

it says that i need to use a trigonometric ratio (sine, cosine, or tangent) to solve for one of the other side lengths.

Answer 7

"tan(C) = AB/BC
AB = BC*tan(C)
= BC*tan(45 degrees)
= 4.5 cm

If one angle is 45 degrees and another is 90 degrees, the other is 45 degrees. So, the triangle is isosceles and so if one leg is 4.5, the other is aswell."

Answer 8

:( well i guess i'll just submit that, thank you though