Brennan is making a poster for the drama club’s new production. It is a regular pentagon with side lengths of 12 inches. The school wants to put up a giant replica of the poster during athletic events.
If the length of each side is 8 times the original, how many times larger is the area of the replica than the area of the original?
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OpenStudy (anonymous):
k
OpenStudy (anonymous):
do you know the area of a pentagon in terms of sides?
OpenStudy (anonymous):
k
OpenStudy (anonymous):
regular polygons have congruent sides
OpenStudy (anonymous):
so the new polygon would have sides 96
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OpenStudy (kinggeorge):
I think it would be a good idea to refer to the set of equations that callisto put up at the end of your second to last question. This is merely a proportions question again.
OpenStudy (anonymous):
12 squared= 144 squared
OpenStudy (anonymous):
96 squared=9216
OpenStudy (anonymous):
9216-144=9072
OpenStudy (kinggeorge):
Don't use subtraction, rather, you should use division.
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OpenStudy (anonymous):
64
OpenStudy (anonymous):
ahh, how many times
OpenStudy (anonymous):
ty
OpenStudy (anonymous):
next problem
OpenStudy (kinggeorge):
Right. You could also have seen this quicker by noticing that since the side lengths increased by a factor of 8, the area must increase by a factor of \(8^2=64\).
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