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Mathematics 20 Online
OpenStudy (anonymous):

Brennan is making a poster for the drama club’s new production. It is a regular pentagon with side lengths of 12 inches. The school wants to put up a giant replica of the poster during athletic events. If the length of each side is 8 times the original, how many times larger is the area of the replica than the area of the original?

OpenStudy (anonymous):

k

OpenStudy (anonymous):

do you know the area of a pentagon in terms of sides?

OpenStudy (anonymous):

k

OpenStudy (anonymous):

regular polygons have congruent sides

OpenStudy (anonymous):

so the new polygon would have sides 96

OpenStudy (kinggeorge):

I think it would be a good idea to refer to the set of equations that callisto put up at the end of your second to last question. This is merely a proportions question again.

OpenStudy (anonymous):

12 squared= 144 squared

OpenStudy (anonymous):

96 squared=9216

OpenStudy (anonymous):

9216-144=9072

OpenStudy (kinggeorge):

Don't use subtraction, rather, you should use division.

OpenStudy (anonymous):

64

OpenStudy (anonymous):

ahh, how many times

OpenStudy (anonymous):

ty

OpenStudy (anonymous):

next problem

OpenStudy (kinggeorge):

Right. You could also have seen this quicker by noticing that since the side lengths increased by a factor of 8, the area must increase by a factor of \(8^2=64\).

OpenStudy (anonymous):

ahh

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