Question

x^2+y^2-3x-4y+4=0 How is this broken down for a circle

Answer 1

first seperate your variables from each other so put all your x's and y's next to each other and then subtract 4

Answer 2

\[(x^2-3x)+(y^2-4y)=-4\]

Answer 3

then complete the squares for x and y

Answer 4

do you know how to do this

Answer 5

I am not real sure how to do this.

Answer 6

Completing the Square method will be used here..

Answer 7

completing the square happens when you have an equation such as

\[x^2+bx=0\] and you want to make it into a perfect square. to do this you take the coefficient b and divide it by two. after dividing it, square it and add it to both sides of the equation. the end product looks like this

\[x^2+bx+\frac{b^2}{2}=\frac{b^2}{2}\]

Answer 8

there is a mistake in the end... the form should be this

\[x^2+bx+(\frac{b}{2})^2=(\frac{b}{2})^2\]

Answer 9

the left side can be factored into a perfect square

\[(x+\frac{b}{2})^2\]=(\frac{b}{2})^2\]

Answer 10

so if you do that with both x and y what do you gte

Answer 11

confused

Answer 12

Thanks for the help!!!