who can solve this

prove that the function represented para metrically by the equations
x= 1/sqrt{1+t^2} - ln (1+sqrt{1+t^2})/(t) , y= t/sqrt{1+t^2} satisfies the relation y=sqrt{1+(dy/dx)^2} = dy/dx

Question

who can solve this 

prove that the function represented para metrically by the equations
x= 1/sqrt{1+t^2} - ln (1+sqrt{1+t^2})/(t) , y= t/sqrt{1+t^2}  satisfies the relation y=sqrt{1+(dy/dx)^2} = dy/dx

anonymous · Answer

$$x= 1/\sqrt{1+t^2} - \ln (1+\sqrt{1+t^2})/(t) , y= t/\sqrt{1+t^2}  $$

anonymous · Answer

$$y \sqrt{1+(dy/dx)^2} = dy/dx$$

anonymous · Answer

hmm... my first idea would be just find bouth differentials dx, dy, and later just find their ratio dy/dx and look if its equal to ysqrt(1+(dy/dx)2 )

anonymous · Answer

ok i'll try it