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Mathematics 25 Online
OpenStudy (anonymous):

Please help with limits? Desperate!! x-->-1. -2 when x

OpenStudy (anonymous):

Here are the options!

OpenStudy (anonymous):

a) lim f(x), x-->-1 from LEFT b)lim f(x), x-->-1 from RIGHT c) lim f(x), x--> 1

OpenStudy (anonymous):

d)lim f(x), x--> 0 from LEFT e) lim f(x), x-->0 from RIGHT f) lim f(x), x--> 0 You have to find them for each of the above prob. PLEASE!!!

OpenStudy (foolaroundmath):

\[f(x) = \begin{cases} -2 & \text{ if } x \le -1 \\ x-1 & \text{ if } -1 <x<0 \\ 0 & \text{ if } 0 \le x \le 3 \end{cases}\] Limit of f(x) at x = a exists if and only if the limit of f(x) as x approaches a from the left = the limit of f(x) as x approaches a from the right. (a) x --> -1 from left. This means x < -1 and is approaching the value of -1. Given the definition of f(x), it is easy to see that for any x < -1, f(x) = -2 So, limit of f(x) as x-->-1 from Left = -2 (b) x--> -1 from right. This means x > -1 and is approaching -1. For x > -1 (and small variations) the corresponding value of f(x) is x-1. So the limit as x --> -1 would be (-1) -1 = -2 So, limit of f(x) as x --> -1 from Right = -2 (c) Since the limit from the left = limit from the right, limit of f(x) as x --> -1 = -2 Can you try (d),(e),(f) along similar lines?

OpenStudy (anonymous):

I have been trying foreverrrr! Do u mind doing them @FoolAroundMath please?

OpenStudy (anonymous):

I just need d, e, and f!

OpenStudy (foolaroundmath):

(d) Limit of f(x) at x --> 0 from LEFT. This means that x is smaller than zero but quite close to zero. x definitely is between -1 and 0 in this case, so the corresponding value of f(x) would be x-1 So, the limit in this case would be 0 -1 = -1 (e) Limit of f(x) at x--> 0 from RIGHT This means that x > 0 but quite closeby (say for example 0.0001). x, in this case lies between 0 and 3 , thus the corresponding value of f(x) is 0. Hence the limit is 0 as well (f) Limit of f(x) at x = 0 from left = -1, from right = 0 As these two limits are not equal, limit of f(x) at x = 0 does not exist.

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