Someone explain or help? A circle has the following equation: x minus 1 quantity squared plus all of y minus 6 the whole squared is equal to 16 over 9 Which statement is true for the circle? Its center is at the ordered pair of 3 over 2, minus 6, and the radius is 16 over 9. Its center is at the ordered pair of 3 over 2, minus 6, and the radius is 4 over 3. Its center is at the ordered pair of minus 3 over 2, 6, and the radius is 4 over 3. Its center is at the ordered pair of minus 3 over 2, 6, and the radius is 16 over 9.
@ nenadmatematika please do you know how to do this?
\[(x-a)^{2}+(y-b)^{2}=r ^{2}\] this is equattion of circle with center at (a,b) and radius r
the equation is \[(x -1)^2 + (y - 6)^2 = \frac {16}{9}\] the general form of a circle is \[(x - h)^2 + (y - k)^2 = r^2\] (h, k) is the centre of the circle and r is the radius. find the centre and take the square root of r^2 to find the radius
so C?
I think..
reading your question the centre is (1, 6) and the radius r = 4/3
which doesn't match any of your listed answers
you've lost me...so the questions is wrong?
nooo you read it wrong lol
either the question is wrong or the answers are wrong...
@campbell_st is right the answers are all wrong, or the question information is wrong
its (x+3/2)*2 + (y+6)*2=16/9
I thought I was blind for a moment because I couldn't see the right answer...so it's possible you didn't write it correctly :D
ahhh
well thats different to the question you typed.
lol i copied and pasted it...from my worksheet.
but anyway, no answer match it, :)
well how would you do it...cause i still need help..
same problem as before no matches
ill rewrite all the answer
this last equation would have center at (-3/2,-6) and radius =4/3
lol that was one of answer chooses! I chose C in the beginning and it was right lol when i was first talking to myko
perhaps you should read a little about the equation of a circle... it may help
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