Question

A rectangle is twice as long as it is wide. If its area is 50 sq. yd., find the length.


10 yd.
25 yd.
33 1/3 yd.

Answer 1

Let the length be x, wts the breadth?

Answer 2

?

Answer 3

Alright first start with your area equations

The area of a rectangle is

\[A=L*W\] where L = Length and W= Width? correct?

Answer 4

correct

Answer 5

Alright and the first statement says that your length is 2 times the size of the width how can you write this as an equality

Answer 6

L=? W

Answer 7

L=2 W

Answer 8

right?

Answer 9

ohh..

Answer 10

yes you're correct

Answer 11

i am?

Answer 12

hold on lol

Answer 13

okay ha

Answer 14

Right it as W= ? L ... if length is 2x larger than width with is one half of L

Answer 15

correct?

Answer 16

2W=L or 1/2L=W

Answer 17

so you were right in the first place i'm just contradicting myself anyways so you have

A=L*W

L=2W

you know the area of the rectangle to be 50 units

50=L*W

Answer 18

uhh.. i dont get it:(

Answer 19

You don't get what?

Answer 20

nevermind.. i get it now

Answer 21

yeah i just replaced A with 50 since it is given

Answer 22

next replace L in the area equation

50=2W*W

Answer 23

\[50=2W^2\] can you solve this?

Answer 24

yes

Answer 25

this will get you your width. Then all you need to do is multiply that by 2 for your length

Answer 26

alright thank you