Question

Complete the square for the equation:
x^2+2x-3=0

a. (x+1)^2=4
b. (x+1)^2=9
c. (x+2)^2=4
d. (x+1.5)=4.25

Answer 1

So..\[x^2+2x=3\]\[x^2+2x+1=3+1\]\[(x+1)^2=4\]

Answer 2

Let me know if you don't understand what I did :).

Answer 3

x^2+2x-3=0
take half of coefficient of x - that is 1:
(x + 1)^2 - 1 - 3 = 0
(x +1)^2 = 4
take square root of both sides to solve for x