OpenStudy (anonymous):

Write the equation of the line that passes through (2, 2) and (6, 3) in standard form.

5 years ago
OpenStudy (anonymous):

Use point-slope form and simplify from there. $y - y_{1} = m(x - x_{1})$

5 years ago
OpenStudy (anonymous):

Standard form is Ax + By = C

5 years ago
OpenStudy (anonymous):

I know the equations...

5 years ago
OpenStudy (anonymous):

So just use them then.

5 years ago
OpenStudy (anonymous):

I got 4x + 4y = 6, is that right?

5 years ago
OpenStudy (anonymous):

I got x - 4y = -6

5 years ago
OpenStudy (anonymous):

$m = \frac{3 - 2}{6 - 2} = \frac{1}{4}$$y - y_{1} = m(x - x_{1})$$y - 2 = \frac{1}{4}(x - 2)$$y - 2 = \frac{x}{4} -\frac{1}{2}$$4(y - 2 = \frac{x}{4} -\frac{1}{2})$$4y - 8 = x - 2$$x - 4y = -6$

5 years ago