Do you do roots of multiplicity in college algebra?
what do you mean?
Because I am studying for my final exam and I just saw the term root of multiplicity... and I don't know what that mean and the term keeps creeping up one me.
(x+2)^2 <--root of multiplicity 2 (x+2)^3 <---root of multiplicity 3 (x+2)^4 <---root of multiplicity 4 bottomline the multiplicity is the exponent
You might also see it like this. THe roots of the polynomial are 3, 2, and 4 multiplicity 2. Find the polynomial. THis means that the roots are 3, 2, 4, 4.
I know about zeros of multiplicity... but that's only if those were equal to zeros... so the first one is -2 is a root of multiplicity 2 like.... :\ Do you know what:\[(x+\sqrt{d})(x-\sqrt{d})\]
-2 is a root of multiplicity 2 would be (x-2)^2 right?
It would be (x + 2)^2 since you would have to reverse solve for x. x= -2. x + 2 = 0
oh wait yeah + sorry :p
once you understand its concept you'll love that thing more than the other kinds of roots because that one is so fast =)))
@Calcmathlete I didn't understand what you said, when you said how you would be given it and asked to find the polynomial..
the roots are 1, 2, and -3 of multiplicity 2. x = 1 x = 2 x = -3 x = -3 the factors would be (x-1)(x-2)(x+3)(x+3)..to find the polynomial multiply those factors
^example
(x-1)^2(x+3)^4(x-2)^2 ???
No. See how it says -3 of multiplicity 2? The multiplicity of 2 only applies to the -3. See how it's repeated?
Why does it only apply to -3?
THat's just how the term works. ee how there's a comma? That separates it.
1, 2, and -3 of multiplicity 2 is the same as 1, 2, -3, and -3.
get it now? :)
@lgbasallote no :'(
which part dont you get?
Okay when you did the roots are 1, 2, and -3 of multiplicity 2. x = 1 x = 2 x = -3 x = -3 the factors would be (x-1)(x-2)(x+3)(x+3)..to find the polynomial multiply those factors it's only -3 of multiplicity 2 and not all of multiplicity 2...
Oh... nvm wrong interpretation of wording... Okay, I get, thanks so much for your help everyone!
haha you're welcome :)
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