Question

find the exact sum

Answer 1

give the exact addends :)

Answer 2

\[\sum_{n=1}^{\infty} 2/n(n+1)\]

\[2/n(n+1)=1/n-1/n+1\]

\[\sum_{n=1}^{\infty} 2/n(n+1) = \sum_{n=1}^{\infty} [1/n-1/n+1]\]

Answer 3

(1-1/2)+(1/2-??)

Answer 4

the last piece is were im stuck

Answer 5

i know you plug in the one into the brackets to obtain 1-1/2 then what do i put 1/2?