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OpenStudy (anonymous):
If p^6=r and p^9=s, which of the following must be equal to p^12 ?
A)2s-r B)2s/r C)s+s/r D)s^2/r E)s^9/r
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OpenStudy (anonymous):
how did you do it
OpenStudy (anonymous):
becuase i tried and i couldnt get anything right
OpenStudy (anonymous):
can you explain what you did but i dont know what you did
hero (hero):
Yeah, in vyew
OpenStudy (anonymous):
vyew??
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OpenStudy (anonymous):
I think hes saying "View"
OpenStudy (anonymous):
Hero i understand it now
OpenStudy (anonymous):
even though you didnt finish explaining it
OpenStudy (anonymous):
I THINK hes working on it so just relax..
OpenStudy (anonymous):
@Hero i think u r wrong....
2X =X+X NOT X*X......
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hero (hero):
s = p^9
s + s/r = p^9 + p^9/p^6
= p^9 + p^3
= p^3^3 + p^3^1
= p^3(3+1)
= p^3^4
= p^12
Therefore, C
OpenStudy (anonymous):
\[a^{n}a^{m}= a^{n+m}\]
\[\frac{a^{m}}{a^{n}}=a^{m-n}\]
use these properties to solve this question!!
hero (hero):
If you have the solution, post it
OpenStudy (anonymous):
\[p^{9} p^{9}=p^{9+9}=p^{18}=s^{2}\]
\[\frac{s^{2}}{r}=\frac{p^{18}}{p^{6}}\]
\[\frac{s^{2}}{r}=p^{12}\]
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