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Simplify. x^2 - 36 over 42 x - 7 x^2
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Is this your question:\[\frac{x^2-36}{42x-7x^2}\]
yes
\[\huge \frac{x^2 - 36}{42x - 7x^2} \implies \frac{(x+6)(x-6)}{7x(6 - x)}\]
i just factored it out
do you know how to solve the problem now??
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no
your like a lightning bolt @lgbasallote
remember that (a-b) = -(b-a) therefore \[\huge \frac{(x+6)(x-6)}{7x(6 - x)} \implies \frac{(x+6)(x-6)}{-7x(x-6)}\] now do you know how to solve it?
I have no idea
hint find the number in the top and bottom then cancel out or get rid off after that u know how to solve it
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remember that \[\huge \frac{ab}{ad} \implies \frac{\cancel a b}{\cancel a d} \implies \frac bd\]
that look the same
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