Question

if 3 is one side and 5 is another side of a triangle, what could the third side be?
dont i just add these two sides together? meaning the third side would 8?

Answer 1

please guys this is an easy question.. just wanna make sure

Answer 2

Is this a right angle triangle?

Answer 3

all the question says is "nancy cuts a piece of cardboard in the shape of a triangle"

Answer 4

@purplec16 -all the question says is "nancy cuts a piece of cardboard in the shape of a triangle"

Answer 5

Well, am pretty sure you don't add them give me a minute to refresh my memory I haven't done this in years..

Answer 6

i am pretty dump with this so i have no idea

Answer 7

dumb** lol

Answer 8

No you're not... and I really don't remember @dpalnc

Answer 9

i didnt think this question was gonna be this hard hehe

Answer 10

It's not hard I just... don't remember but I'm pretty sure you don't add them...

Answer 11

Generally area of triangle is given by, A = 1/2 x base x height

or Area = 1/2 x one side x other side x sin of angle opposite opposite to unknown side..

Look if it can help !!!

Answer 12

@aria11 what you need to know about triangle is that the sum of two sides should be greater than the third side so let's say the third side is x

5 + 3 > x so 8 > x

so the third side could be 8 and below but wait remember i said sum of two sides must be greater than the third so the sum of x and 3 should be greater than 5

x + 3 > 5
x > 2

so the third side should be greater than 2 but less than 8 so

2<x<8

got that?

Answer 13

hi use pythagourus theorm.

Answer 14

She doesn't know if it's a right angle triangle so she can't use pythagorean @muhammad9t5

Answer 15

find angle between them first.

Answer 16

or use law of cosine.

Answer 17

friend i thinnk you also should have an angle then you can solve it easily.

Answer 18

There is more sine called sine rule, you may use that if you know all angles as well..

a/SinA = b/ SinB = c/ SinC

Answer 19

hi now i am on your problem. Solution is let us consider that 3 is adjacent and 5 is hypotenuse therefore
cosx=adjacent/hyp
cosx=3/5
cosx=0.6
x=\[\cos^{-1} 0.6 \]
x=53.13 deg
wae have found angle now we have to find the side
\[c ^{2}=a ^{2}+b ^{2}-2abcocx\]
\[c ^{2}=3^{2}+5^{2}-2\times3\times5\times0.6\]
\[c ^{2}=9+25-18\]\[c ^{2}=34-18\]
\[c ^{2}=16\]
c=4
i hope it works.