Question

2(x-1)^3=x+1

Answer 1

hmm okay?

Answer 2

can u solve it?

Answer 3

???

Answer 4

solve for x?

Answer 5

yeah

Answer 6

here's my thought
let x - 1 = a
therefore a +1 = x

2a^3 = a + 1 + 1
2a^3 = a + 2
2a^3 - a - 2 = 0

does that give you any ideas?

Answer 7

2(x-1)^3=x+1 noo sorry not really can u tell me how to do it just by factoring etc?

Answer 8

lol that's what im thinking too

Answer 9

@myininaya pls help here

Answer 10

Hey @lgbasallote what was wrong with your way?

Answer 11

It seems to be awesome! :)

Answer 12

i don't know what to do next lol

Answer 13

Try doing a little of testing possible rational zeros for what you have

Answer 14

Synthetic division will come in handy

Answer 15

you heard her @louis413 ;)

Answer 16

lol im only in alg/trig in high schooll.. loll wut is that?

Answer 17

oh wait i think i made a mistake anyways...
let me try again
but yeah that is what i would do test to see if any possible rational zeros work

Answer 18

algebra/trig?
which one?

Answer 19

well im takling the algebra2/trig course right now at summer school

Answer 20

synthetic division and looking at possible rational zeros are in algebra

Answer 21

ok so what have you learned then?

Answer 22

factoring... quadratic formula completeing the squares etc

Answer 23

And is your equation written correctly?

Answer 24

yes can it be solved like 2(x-1)^2(x-1)-1(X-1)=0

Answer 25

I can only see to find a real approximation by looking at the graph and seeing where it crosses the x-axis

Answer 26

would you like to go for a trignometric solution?
might seem complicated but is easy..
involves inverse function just a bit..and sin 3x etc formullas ?

Answer 27

well..
in 2a^3 - a - 2 = 0
let a = m sin y
=> 2m^3 sin^3 y - msin y -2 =0
multiplying both sides by (-2/m^3)
=> -4sin^3 y + 2sin y/(m^2) + 4/(m^3) =0
our aim is to convert this in the form of
-4sin^3 y + 3 siny which will convert it into sin 3y and simplify things
we have to chose a particular value of m for that purpose
in our case
2/m^2 = 3
or m = sqrt(3/2) and -sqrt(3/2)
thus we have these 2 eqns :
-4sin^3 y + 3sin y + 8sqrt(2)/(3sqrt(3)) = 0
and
-4sin^3 y + 3sin y - 8sqrt(2)/(3sqrt(3)) = 0

=> sin 3y = - 8sqrt(2)/(3sqrt(3))
and
=>sin 3y = 8sqrt(2)/(3sqrt(3))

now using any scientific calculator, we may find value of y,then a(=msin y)
and then finally x(=a+1)

Answer 28

hope i was able to explain well..