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\[integrate => \int\limits 3^{2x}dx\]
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Ohkay, Mr. Paul McCartney, let me provide you with a standard formula for this, and see if you can work this out: \[\Large \int a^{px+q}.dx = \frac{a^{px+q}}{p(\ln a)}\] a,p and q are constants.
2x=t 2dx=dt \[\int\limits \frac{3^{t}dt}{2}\] \[=\frac{1}{2} \frac{3^{t}}{\ln3}\]
\[\frac{1}{2}*3^{2x}*\frac{1}{\ln3}\]
|Thanks! :)
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