Question

A regular octagon has side length 10.9 in. The perimeter of the octagon is 87.2 in and the area is 392.4 in2. A second octagon has side lengths equal to 5.45 in. Find the area of the second octagon.
61.60 in2

75.24 in2

37.06 in2

98.09 in2

Answer 1

the ratio of areas of the octagon's = ratio of squares of the sides
using the sides of 2 octagons:
ratio is 10.9 / 5.45 = 2/1

so the areas are in ratio 4:1
4/ 1 = 392.4 / a where a is area of the second octagon

Answer 2

so area = 392.4 / 4