Question

limit n tend to( n^2*e^-n)the sequences is converge or diverge

Answer 1

\[\lim_{x \rightarrow \infty} \frac{x^2}{e^x}\]

Answer 2

use Hopital rule twice

Answer 3

can u solve it

Answer 4

\[\lim_{x \rightarrow \infty} \frac{x^2}{e^x}=\lim_{x \rightarrow \infty} \frac{2x}{e^x}=\lim_{x \rightarrow \infty} \frac{2}{e^x}=\lim_{x \rightarrow \infty} \frac{2}{\infty}=0\]

Answer 5

then the the sequences is converge

Answer 6

thanks borther.. jazak ALLAH

Answer 7

MARHABA

Answer 8

BROTHER IN THE 3RD STEP ONLY 2/e^x where is x..? i mean 2x rather tthen x why.. can u explain it.

Answer 9

oho brother again derivative..?

Answer 10

plz bro ans this question

Answer 11

please post each question separately
thanks :)