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determine the taylor series about point x (subscript)0=5 for the function x^2
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\(x^2\) is a polynomial, so the taylor series will be finite, i.e. it will look like \[a(x-5)^2+b(x-5)+c\]
put \(f(x)=a(x-5)^2+b(x-5)+c\) then \(f(5)=c\) and so \(c=25\)
then \(f'(x)=2a(x-5)+b\) and so \(f'(5)=b\) hence \(b=10\)
guess i am alone here ok
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