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SOLVE. u2 + 2u − 4 = 0
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well, do you know the quadratic formula?
Do you mean:\[u^2 + 2u - 4 = 0\]
Yes I meant u^2+2u-4=0. I am lost with this one!
do you know that quadratic formula?
You can solve this with the quadratic formula. \[(-b \pm \sqrt{b^2 - 4(a)(c)}) / 2(a)\]
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u=−2+/−22−4(1)(−4)−−−−−−−−−−−√/(2) =−2+/−20−−√/(2) =−2+/−4×5−−−−√/(2) =−2+/−25√/(2) factor out a 2 from the top =2(−1+/−5√)/(2) divide the top and bottom by 2 u=−1+/−5√
No James, I do not. He didn't give it to us and his example confuses me!
-2 +/- sqrt(2^2 - 4(1)(-4)) (-2 +/- sqrt(20))2 = (-2 +/- sqrt(4 x 5)) / 2 (-2 +/- 2(sqrt)(5)) / 2 -1 +/- 1(sqrt)(5) \[-1 \pm \sqrt[1]{5}\]
That's your answer! :)
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