Find the initial value problem dy/dx=5x^-14/15 I got this answer wrong on my test need worked showed out step by step do not understand this to much
\[\Large {dy \over dx}=5x^{(-14/15)}\]is this what you mean????
yes
don't you also need a 2nd piece of information ... y(a)=b or are you just having trouble with the integration?
yes missing a piece sorry y(-1)=-3
\[\Large y=5\int\limits x^{(-14/15)}dx\]
yes i get that far but after that i am completly lost
\[\large -{14 \over 15} +1 = {1\over15}\]
ohh ok i see that part
\[\Large y= 5\cdot {x^{(1/15)}\over 1/15}+C\]
\[\LARGE =75\cdot \sqrt[15]{x}+C\]
y=75x^1/15+C
yes ... now you just have to plug in x=-1 , y=-3 ... to solve for C
oh okay i see now i was not understanding the part you just worked out but i understand now
the final answer is 75x^1/15+72 ???
\[\Huge \checkmark\] y(0)=72
ok thanks for your help
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