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OpenStudy (anonymous):
Find the initial value problem
dy/dx=5x^-14/15
I got this answer wrong on my test need worked showed out step by step do not understand this to much
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OpenStudy (paxpolaris):
\[\Large {dy \over dx}=5x^{(-14/15)}\]is this what you mean????
OpenStudy (anonymous):
yes
OpenStudy (paxpolaris):
don't you also need a 2nd piece of information ... y(a)=b
or are you just having trouble with the integration?
OpenStudy (anonymous):
yes missing a piece sorry
y(-1)=-3
OpenStudy (paxpolaris):
\[\Large y=5\int\limits x^{(-14/15)}dx\]
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OpenStudy (anonymous):
yes i get that far but after that i am completly lost
OpenStudy (paxpolaris):
\[\large -{14 \over 15} +1 = {1\over15}\]
OpenStudy (anonymous):
ohh ok i see that part
OpenStudy (paxpolaris):
\[\Large y= 5\cdot {x^{(1/15)}\over 1/15}+C\]
OpenStudy (paxpolaris):
\[\LARGE =75\cdot \sqrt[15]{x}+C\]
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OpenStudy (anonymous):
y=75x^1/15+C
OpenStudy (paxpolaris):
yes ... now you just have to plug in x=-1 , y=-3 ... to solve for C
OpenStudy (anonymous):
oh okay i see now i was not understanding the part you just worked out but i understand now
OpenStudy (anonymous):
the final answer is 75x^1/15+72 ???
OpenStudy (paxpolaris):
\[\Huge \checkmark\]
y(0)=72
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OpenStudy (anonymous):
ok thanks for your help
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