Let ABC be an equilateral triangle and let P be a point
inside the triangle such that
PA=3
PB=4
PC=5
Find the area of the triangle ABC.

Question

Let ABC be an equilateral triangle and let P be a point
inside the triangle such that
PA=3
PB=4
PC=5
Find the area of the triangle ABC.

anonymous · Answer

Area of ABC = $\large \frac{x\sqrt3}{2}\cdot x \cdot \frac{1}{2}=\frac{x^2\sqrt3}{4} $

anonymous · Answer

You do not know x.

anonymous · Answer

Hey, wouldnt the point P create 3 sub triangles within ABC? So you could calculate the total area by adding each sub area. Like,
PA * PB over 2 + PB * PC over 2 + PA * PC over 2?

anonymous · Answer

still trying doc...:)
law of cosines...,

anonymous · Answer

oh nevermind, thats just wrong

anonymous · Answer

$\large x^2=3^2+4^2-2(3)(4)cos\theta $

anonymous · Answer

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