Question

Let ABC be an equilateral triangle and let P be a point
inside the triangle such that
PA=3
PB=4
PC=5
Find the area of the triangle ABC.

Answer 1

Area of ABC = \(\large \frac{x\sqrt3}{2}\cdot x \cdot \frac{1}{2}=\frac{x^2\sqrt3}{4} \)

Answer 2

You do not know x.

Answer 3

Hey, wouldnt the point P create 3 sub triangles within ABC? So you could calculate the total area by adding each sub area. Like,
PA * PB over 2 + PB * PC over 2 + PA * PC over 2?

Answer 4

still trying doc...:)
law of cosines...,

Answer 5

oh nevermind, thats just wrong

Answer 6

\(\large x^2=3^2+4^2-2(3)(4)cos\theta \)