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Assume that the readings on the thermometers are normally distributed with a mean of 0 and a standard deviation of 1.00. A thermometer is randomly selected and tested. Find the temperature reading corresponding to P88, the 88th percentile. This is the temperature reading between 88% from the top 12%.
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you need a calculator or z score table as you are using fractions of standard deviation. I can tell you this though 88th percentile is between 1 and 2 standard deviations from the mean so somewhere between 1.00 and 2.00
How do I look for it on the Z score table?
Find the value of z corresponding to a probability of .8800. This is the answer in degrees.
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