Mathematics
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OpenStudy (anonymous):
Can someone please help me find this derivative I know the answer but I don't get how to find it :
x (x^2 + 1) ^(-1/2)
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OpenStudy (anonymous):
The step I am up to is 1 (x^2 + 1) ^ (-1/2) + x (-1/2) (x^2 + 1) ^-3/2 (2x) but I don't know where to go after this
OpenStudy (anonymous):
(x^2 + 1) ^ (-1/2) is common in both
OpenStudy (anonymous):
take it out and then add
OpenStudy (anonymous):
?
OpenStudy (anonymous):
can you elaborate further? add ?
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OpenStudy (anonymous):
like can you show me
OpenStudy (anonymous):
(x^2 + 1) ^ (-1/2) [ 1 + x (-1/2) (x^2 + 1) ^-1 (2x) ]
OpenStudy (anonymous):
is this clear? :)
OpenStudy (anonymous):
ok the final answer was 1 / (x^2 + 1) ^ -3/2 how would u get that from this?
OpenStudy (anonymous):
?
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OpenStudy (anonymous):
? can i get an answer
OpenStudy (anonymous):
well...i am not getting that answer :|
OpenStudy (anonymous):
yeah that is the correct answer though
OpenStudy (anonymous):
can someone thats looking at this prob guide me through with steps?
OpenStudy (asnaseer):
Is this the equation you are trying to differentiate?\[x\sqrt{x^2+1}\]
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OpenStudy (asnaseer):
sorry - I meant:\[\frac{x}{\sqrt{x^2+1}}\]
OpenStudy (anonymous):
yeah asnnaseer!
OpenStudy (anonymous):
i got it :D
OpenStudy (anonymous):
Can you guide me through from the beginning?
OpenStudy (anonymous):
please
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OpenStudy (asnaseer):
ok - it looks like @telltoamit has got it so I'll let him/her explain it to you...
OpenStudy (anonymous):
(x^2 + 1) ^ (-1/2) [ 1 + x (-1/2) (x^2 + 1) ^-1 (2x) ]
=
(x^2 + 1) ^ (-1/2) [ 1 - x^2 (x^2 + 1) ^-1 ]
OpenStudy (anonymous):
(x^2 + 1) ^ (-1/2) [ (x^2 + 1) ^-1 ]
OpenStudy (anonymous):
thats ur answer
OpenStudy (anonymous):
clear?
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OpenStudy (anonymous):
yeah thankss
OpenStudy (anonymous):
You're welcome :)