Question

Rationalize the denominator in the expression.
sq. root of 12x^7 over sq. root of y^9

Answer 1

there was no reason for issuing warning letter

Answer 2

first off \(\sqrt{y^9}=\sqrt{y^8}\sqrt{y}=y^4\sqrt{y}\) and similarly
\[\sqrt{12x^7}=\sqrt{4x^6}\sqrt{3x}=2x^3\sqrt{3x}\] so you should start with
\[\frac{2x^3\sqrt{3y}}{y^4\sqrt{y}}\]

Answer 3

oops typo there, should be
\[\frac{2x^3\sqrt{3x}}{y^4\sqrt{y}}\]

Answer 4

you are making this more and more complicated