k=1 sigma k tends to infinity (-3/2)^(k+1) determine whether series converges or diverges if series is converges find the sum

Question

anonymous · Answer

hey
did you get my answer to the last one? the site froze and i could not complete it

turingtest · Answer

I gave an answer to this already

turingtest · Answer

$$\sum_{k=1}^\infty(-\frac32)^2(-\frac32)^{k-1}$$

experimentx · Answer

did you mean??
$$ \sum_{k = 1}^{\infty} \left ( \frac{-3}{2} \right ) ^{k+1}$$
also don't close question and ask new one. redundancy is no better than spam

anonymous · Answer

not much to this one as the terms grow infinitely large for k odd (k+1 even) and go to minus infinity if k is even (so k + 1 is odd)
cannot converge

anonymous · Answer

turing test u not clearly ans this question half ans u give me not a final answer

experimentx · Answer

The converging alternate seris should be like 1)
and the diverging alternate series whousl be like 2)
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