Find the vertex of the parabola and give its direction of opening. x=1/2y^2+3y-6?

Question

anonymous · Answer

Can someone just tell me if my answer is right? The vertex is (-21/2, -3). <----    *opens to the right*

anonymous · Answer

@timo86m  is that correct

anonymous · Answer

you can graph it

anonymous · Answer

https://www.google.com/search?rlz=1C1CHFX_enUS470US470&sugexp=chrome,mod=8&sourceid=chrome&ie=UTF-8&q=1%2F2y%5E2%2B3y-6

anonymous · Answer

So it opens up?!!

anonymous · Answer

it is odd could be a trick questions since it is f(y) not f(x)  lol

anonymous · Answer

how'd you do it did you solve for y?

anonymous · Answer

x= 1/2y^2 + 3y - 6

  x = (1/2)(y^2 + 6y) - 6 
        x = (1/2)(y^2 + 6y + 9) - 6 - 9/2
               x = (1/2)(y + 3)^2 - 21/2.

The vertex is (-21/2, -3). <----    *opens up*

anonymous · Answer

Thats correct

anonymous · Answer

It opens to the right, never mind

anonymous · Answer

i just graphed it

anonymous · Answer

that is what i said solve for y  it is in f(y) form not f(x) form

anonymous · Answer

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