Question

Find the vertex of the parabola and give its direction of opening. x=1/2y^2+3y-6?

Answer 1

Can someone just tell me if my answer is right? The vertex is (-21/2, -3). <---- *opens to the right*

Answer 2

@timo86m is that correct

Answer 3

you can graph it

Answer 4

https://www.google.com/search?rlz=1C1CHFX_enUS470US470&sugexp=chrome,mod=8&sourceid=chrome&ie=UTF-8&q=1%2F2y%5E2%2B3y-6

Answer 5

So it opens up?!!

Answer 6

it is odd could be a trick questions since it is f(y) not f(x) lol

Answer 7

how'd you do it did you solve for y?

Answer 8

x= 1/2y^2 + 3y - 6

x = (1/2)(y^2 + 6y) - 6
x = (1/2)(y^2 + 6y + 9) - 6 - 9/2
x = (1/2)(y + 3)^2 - 21/2.

The vertex is (-21/2, -3). <---- *opens up*

Answer 9

Thats correct

Answer 10

It opens to the right, never mind

Answer 11

i just graphed it

Answer 12

that is what i said solve for y it is in f(y) form not f(x) form