Question

PLEASE HELP. All of the triangles in the figure below are congruent. What is the area of the figure? Note that all measurements are in centimeters. Note that the apothem shown is equal to 2sqrt3. 24sqrt3cm2

36 + 24sqrt3cm2

36sqrt3cm2

24 + 36sqrt3cm2

Answer 1

Since the apothem is \(2\sqrt3\) what is the height of one of the equilateral triangles?

Answer 2

3?

Answer 3

Wait a second... That diagram is really confusing me. They have something labeled as length 3, but if the apothem is \(2\sqrt3\), that can't be the height of the triangle.

Answer 4

Oh, well I'm really confused. haha

Answer 5

I think we just have to assume that they are not equilateral triangles. In that case, the height can be 3, and the apothem \(2\sqrt3\) without a problem.

Given that the height of the triangles is 3, and the base is 4, what is the area of one of the triangles?

Answer 6

12?

Answer 7

Close, remember that the formula for the area of a triangle is \(\frac{1}{2} bh\), so it should be \[\frac{1}{2}3\cdot4=\frac{12}{2}=6\]Is you area of a single triangle. Using this, can you tell me the area of all 6 triangles?

Answer 8

\[\frac{3\cdot4}{2}=6\]not 24.

Answer 9

waite

Answer 10

the erea out side is
(3*4)/2=6
and you have 6 triangle : 6*6=36
now you need find erea inside

Answer 11

It would be best if the asker would contribute some to the problem solving process as well.

Answer 12

its 36 what do I do from there

Answer 13

inside hve 6 side
360/6= 60 degree
60/2=30 degree