Question

What is true about the solutions of a quadratic equation when the radicand of the quadratic formula is a perfect square?

No real solutions

Two identical rational solutions

Two different rational solutions

Two irrational solutions

Answer 1

rational, and they can be unequal, a trinomial or equal for a perfect square

Answer 2

so its C?

Answer 3

say \(b^2-4ac=m^2\)
\[\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-b\pm\sqrt{m^2}}{2a}=\frac{-b \pm m}{2a}\] two rational numbers unless of course \(m=0\) which is also a perfect square but seems to be ignored in this question

Answer 4

thats would be my choice

Answer 5

yeah mine too, even though strictly speaking it is wrong

Answer 6

lol alright thank you guys

Answer 7

I agree... as a perfect square will have a square number for the discriminant....

Answer 8

so what do you mean.. its B?

Answer 9

no its C but a poorly worded question