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Determine whether the sequence converges or diverges, then compute the limit {(2n-1)!/(2n+1)!}
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I have never dealt with factorials before can anyone help me solve this?
can we use the ratio test, or is that only for series?
that is just for series
thought so...
just simplify and take the limit
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\(n! = 1.2.3...n = (1.2.3.....(n-1)).n = n.(n-1)!\) This is a fundamental property of factorials. Now, the sequence that we have is \[a_{n} = \frac{(2n-1)!}{(2n+1)!}=\frac{(2n-1)!}{(2n-1)!.2n.(2n+1)} = \frac{1}{2n(2n+1)}\] can you take it off from here?
ah, I see it now :0
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