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9^(x/2)
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\[9^{x/2}\]
and what you need here ?
I am confused as to how problems like this simplify... I know that it simplifies to 3^x... but how does that work?
Are you typing something Calcmathlete?
\[9^{\frac{x}{2}} = (\sqrt{9})^{x} = 3^{x}\]
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So that is a true statement for any power problem?
Well, are you familiar with turning fractional exponents to radicals?
\[a ^{m/n} = \sqrt[n]{a}^{m}\]
Yes, I am familiar. I am in calculus 2... I wasn't sure if that rule would apply to a base if it had a variable as an exponent.
It still works.
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ok. so... 16^x/4 = 2^x?
Yeah. \[\sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m}\]
This problem arose from an integral. \[\int\limits_{-2}^{2}9^{x/2} dx\] so that is the same as... \[\int\limits_{-2}^{2}3^{x} dx\]?
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