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Mathematics 20 Online
OpenStudy (anonymous):

9^(x/2)

OpenStudy (anonymous):

\[9^{x/2}\]

OpenStudy (anonymous):

and what you need here ?

OpenStudy (anonymous):

I am confused as to how problems like this simplify... I know that it simplifies to 3^x... but how does that work?

OpenStudy (anonymous):

Are you typing something Calcmathlete?

OpenStudy (anonymous):

\[9^{\frac{x}{2}} = (\sqrt{9})^{x} = 3^{x}\]

OpenStudy (anonymous):

So that is a true statement for any power problem?

OpenStudy (anonymous):

Well, are you familiar with turning fractional exponents to radicals?

OpenStudy (anonymous):

\[a ^{m/n} = \sqrt[n]{a}^{m}\]

OpenStudy (anonymous):

Yes, I am familiar. I am in calculus 2... I wasn't sure if that rule would apply to a base if it had a variable as an exponent.

OpenStudy (anonymous):

It still works.

OpenStudy (anonymous):

ok. so... 16^x/4 = 2^x?

OpenStudy (anonymous):

Yeah. \[\sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m}\]

OpenStudy (anonymous):

This problem arose from an integral. \[\int\limits_{-2}^{2}9^{x/2} dx\] so that is the same as... \[\int\limits_{-2}^{2}3^{x} dx\]?

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