Question

question will be attached
Suppose the function shown below was expressed in standard form,

Answer 1

hmm do you know the x-intercepts of the graph?

Answer 2

nope thats allll I got

Answer 3

you can actually figure it out by looking at the graph...at what point in the x axis does the graph intersect the x axis?

Answer 4

D? -2?

Answer 5

first tell me what the x-intercepts are

Answer 6

there are two x intercepts

Answer 7

-4 and -2

Answer 8

good..now..the x-intercepts of a quadratic function is also the zeroes of the quadratic function so you have

x = -4
x = -2

Answer 9

now...you can turn them into factors correct?

(x+4)(x+2)

Answer 10

now FOIL it

Answer 11

x^2+6x+8

Answer 12

so what's a?

Answer 13

1
but when i graph it it looks different

Answer 14

really? how so?

Answer 15

http://www.wolframalpha.com/input/?i=x^2+%2B+6x+%2B+8&dataset=

looks same to me

Answer 16

bit on the original question it goes all the way down to -2

Answer 17

hmm good point...

Answer 18

do you know the equation of a parabola?

Answer 19

no :(

Answer 20

i really think what i did was right..the a would really be 1 :/

Answer 21

i believe you cuz it made since and like we used the two x points but idk

Answer 22

http://www.wolframalpha.com/input/?i=2x^2+%2B+12x+%2B+16

Answer 23

so it would be B

Answer 24

is B the one with 2 coefficient? im not viewing the question anymore lol im lagged

Answer 25

yeah

but how did you figure that out that it is 2x^2 + 12x + 16

Answer 26

well i know x^2 + 6x + 8 the only one with x-intercepts -4 and -2

but since it wasnt right...i multiplied the equation by 2 so i got 2x^2 + 12x + 16

Answer 27

ohh ok cool thanks!! :)

Answer 28

you're welcome