Question

The sum of the real roots of the equation Ix-2I^2 + Ix-2I-2=0 is -
a)2 c)4
b)6 d) 8

Answer 1

@nitz

Answer 2

\[\left| x-2 \right|^{2}+\left| x-2 \right|-2\]

Answer 3

=0

Answer 4

x=3,1,0,4

Answer 5

is it?

Answer 6

ans. 4 (sum of real roots)

Answer 7

see what i think i can explain you

Answer 8

put \[\left| x-2 \right|=t\]

Answer 9

the equation becomes;
\[t ^{2}+t-2=0\]

Answer 10

t=1 and t=-2

Answer 11

got it.

Answer 12

when t=1;

\[\left| x-2 \right|=1\]

Answer 13

ok ok i got it.

Answer 14

x-2=1 and x-2=-1
x=3 and x=1
so the sum is 4


in second case:
when t=-2
\[\left| x-2 \right|=-2\]

Answer 15

x-2=-2 and x-2=2
x=0 and x=4
sum is 4 again

Answer 16

nitz wait

Answer 17

mod of x-2 cant be equal to a negative no.
So it will be rejected??

Answer 18

ya right it will be rejected as mod(X) is always positive
good haan

Answer 19

ok thanks
need you on some more.

Answer 20

ya sure