Question

Solve the proportion 2/x= √3+1/5

Answer 1

@tamlin first of all welcome to openstudy .

\[\huge{\frac{2}{x}=\sqrt{3}+\frac{1}{5}}\] is this the question ?

Answer 2

except 3+1 is under a longer line together

Answer 3

Aha

\(\Rightarrow \Large {2 \over x} = {\sqrt{3 + 1} \over 5} \)

Answer 4

\(\Rightarrow \Large{ 2 \over x} = {{\sqrt3 } + 1 \over 5} \)

\(\Rightarrow 2 \times 5 = x(\sqrt3 + 1) \)

Answer 5

ok :
\[\huge{\frac{2}{x}=\sqrt{3}+\frac{1}{5}}\]
\[\huge{\frac{2}{x}=\frac{(5\sqrt{3}+1)}{5}}\]
\[\huge{2*5 = x* (5\sqrt{3}+1)}\]

Answer 6

\(\Rightarrow 10 = x\sqrt3 + x\)

Can you solve?

Answer 7

You're welcome :)

Answer 8

from my side too..

Answer 9

\(\Rightarrow 10 - x = x\sqrt3\)

\(\Rightarrow \Large {10 - x \over \sqrt3} = x\)

\(\Rightarrow \Large{10\sqrt{3} - x\sqrt 3 \over 3} = x\)

\(\Rightarrow 3x = 10\sqrt3 - x\sqrt3\)

Can you solve now?

Answer 10

\(\Rightarrow 3x = (10 - x)\sqrt3\)

\(\Rightarrow \Large {3x \over \sqrt3} = 10 - x\)

\(\Rightarrow \Large {3x\sqrt3 \over 3} = 10 - x\)

\(\Rightarrow 3x\sqrt3 = 30 - 3x\)

\(\Rightarrow 3x\sqrt 3 - 30 = -x\)

\(\Rightarrow x = -3x\sqrt3 + 30\)