Question

Solve for x :
(Logarithms)

Answer 1

\[\log_{4}(3-x)+\log_{0.25}(3+x)= \log_{4}(1-x)+\log_{0.25}(2x+1)\]

Answer 2

x = 0 or 7

Answer 3

solution please!!

Answer 4

actually i m not familiar with equation tool here.

so do one thing convert each term to base 2

using log\[\log_{a ^{n}}x = 1/nlog_{a}x \]

get all things together leaving zero on one side
then its easy to solve

Answer 5

note that 4 = 1/0.25
or log 0.25 = -1
where base is 4
so converting everything to base 4,
log (3-x) - log(3+x) = log(1-x) - log(2x+1)
=> (3-x)/(3+x) = (1-x)(2x+1)
just solve for x