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Mathematics 21 Online
OpenStudy (anonymous):

Differentiate tan^3x with respect to x

OpenStudy (anonymous):

\[3 \tan ^{2 }x \sec ^{2} x\] if i am not wrong

OpenStudy (anonymous):

From here... \[\frac{d}{dx}(\tan^3(x))\] power rule, then chain rule \[ 3 \tan^2(x) (\frac{d}{dx}(\tan(x)))\] derivative of tangent is sec^2 \[3 \tan^2(x) \sec^2(x)\ dx\]

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