In △DEF, what is the length of DF ?
90
45√2
15√3
30√3
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OpenStudy (hang254):
OpenStudy (callisto):
Use sine ratio to find DF
\[sin60 = \frac{45}{DF}\]
OpenStudy (hang254):
(45)sin60 = 38.97114317
OpenStudy (callisto):
Not really.
OpenStudy (hang254):
so then???
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OpenStudy (callisto):
Multiply both sides by DF. Then divide both sides by sin60. What do you get?
OpenStudy (hang254):
I dont know what DF equals
OpenStudy (ganpat):
ok... Sin 60 = 45/ DF
Therefore DF = 45/ sin 60 = 45/\[\sqrt{3}/2\] = 90/ sq rt 3...
OpenStudy (hang254):
oh, ok. So 51.96
OpenStudy (hang254):
so, 30 sqrt 3
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OpenStudy (ganpat):
yup.. 51.96.. if u simplify further...
OpenStudy (callisto):
Hmm You'll now what DF equal to
\[sin60=\frac{45}{DF}\]Multiply both sides by DF.
\[DFsin60=DF(\frac{45}{DF})\]\[DFsin60=45\]
Then divide both sides by sin60.
\[\frac{DFsin60}{sin60}=\frac{45}{sin60}\]\[DF=\frac{45}{sin60}=...\]