not sure if I did hat right... Idk if I am able to pull out that 1/x?
OpenStudy (anonymous):
Apply U sub, it works fine!
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OpenStudy (ash2326):
@KonradZuse We don't need to do by parts here
\[\int \frac{(\ln x)^3}{x}dx\]
put
\[\ln x= t\]
we get
\[\frac{dx}{x}=dt\]
so our integral becomes
\[\int t^3 dt\]
I think you can solve from here!!
OpenStudy (konradzuse):
oh crap I messed up... it should have been x^-1
OpenStudy (konradzuse):
but okay.. hmm...
OpenStudy (ash2326):
Yeah, did you get it?
OpenStudy (konradzuse):
yeah makes sense. dx/x = dt or dx = xdt? so it would be xt^3/x so the x's cancel out.
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