I need help finding an equation and writing it in both slope intercept form and standard form.
Through (6,-3) and (8,4)

Question

I need help finding an equation and writing it in both slope intercept form and standard form. 
Through (6,-3) and (8,4)

campbell_st · Answer

find the gradient  
 
$$m = \frac{ y _{2} -y _{1}}{x _{2} - x}$$

$$m =\frac{( 4 - -3)}{(8-6)}$$

m = 7/2

then the equation of the line is 

$$y =\frac{7}{2} x + b$$

substitute x = 8 and y = 4 from the 2nd point into the equation above and solve for b. 

this will give the equation of the line in slope- intercept form

anonymous · Answer

i got 7/2x+24 for slope intercept

anonymous · Answer

I got 7x+2y=64 for the standard form but I wasn't sure if it was correct..

campbell_st · Answer

isn't it

4 = 7/2 * 8 + b

4 = 28 + b

subtract 28 from both sides so

-24 = b

then the equation is 

y = 7/2 x - 24

anonymous · Answer

Yes you're right ..small mistake

campbell_st · Answer

thats ok... happens to us all

anonymous · Answer

Is the standard form 7x+2y=64

campbell_st · Answer

y = 7/2 x - 24

multiply every term by 2

2y = 7x - 48

add 48 to both sides and subtract 2y from both sides 

7x - 2y = 48

anonymous · Answer

doesn't it have to be in Ax+By=C form so it would be 7x+2y=48

campbell_st · Answer

you need to rearrange the equation... in my solution A = 7, B = -2 and C = 48

campbell_st · Answer

thats just the general form, A,B,C can be positive or negative

anonymous · Answer

can you help me with one more problem?