Question

sqrt (x + b) = sqrt (x- b) +2

Answer 1

Is the question
(1)\[\sqrt{x+b} = \sqrt{x-b+2}\]Or (2)\[\sqrt{x+b} = \sqrt{x-b}+2\]

Answer 2

the second one

Answer 3

How do you think this will be solved?

Answer 4

Sorry I made a serious mistake there.
But... still, what do you need to find?

Answer 5

the value of x

Answer 6

Is \(b\) constant?

Answer 7

Ok ! so first of all @broncos1fan
\[\huge{\textbf{Welcome to openstudy}}\]

So here i go with the solutions/hints :
\[\huge{\sqrt{x+b}=\sqrt{x-b}+2}\]
\[\huge{(\sqrt{x+b})^2=[(\sqrt{x-b}+2)]^2}\]
\[\huge{x+b=x-b+4+2\sqrt{x-b}(2)}\]

Answer 8

Will this work @Limitless

Answer 9

@mathslover Do you know if the asker need to solve b or x? either way, we can only express an unknown in terms of another unknowns..

Answer 10

*needs

Answer 11

@mathslover, yup. Your last line should read \(x+b=x-b+4+4\sqrt{x-b}.\) @broncos1fan can solve for \(x\) from here.

Answer 12

b is constant

Answer 13

\[\huge{x+b-x+b=4+2\sqrt{x-b}2}\]
\[\huge{2b-4=4\sqrt{x-b}}\]
\[\huge{\frac{2b-4}{4}=\sqrt{x-b}}\]
square both sides ... and get the answer in terms of b for x

Answer 14

@mathslover, no need to solve it that far.

Answer 15

ok! sorry for that

Answer 16

I believe all that is desired by this exercise is learning the trick of removing radicals.

Answer 17

@broncos1fan, do you understand?

Answer 18

yes

Answer 19

Wonderful. Have a good day now.

Answer 20

thank you you too