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Mathematics 16 Online
OpenStudy (anonymous):

I am trying to find the sums and differences of logarithms

OpenStudy (lgbasallote):

do you have a specific problem?

OpenStudy (anonymous):

\[\ln \sqrt[4]{ab ^{2}}\]

OpenStudy (lgbasallote):

ahh..you know that \(\sqrt[4]{ab^3} \implies (ab^3)^{1/4}\) right?

OpenStudy (anonymous):

yes. i just don't know what the final answer should look like.

OpenStudy (lgbasallote):

so basically \[\large \ln (\sqrt[4]{ab^3} \implies \ln (ab^3)^{1/4}\] now i can use power rule \[\large \frac{1}{4} \ln (ab^3)\] now i apply the multiplication law of logarithms \[\frac 14 \ln a + \frac14 \ln b^3\] now i apply power rule again \[\frac 14 \ln a + \frac 34 \ln b\] do you get that?

OpenStudy (anonymous):

I have \[ab^{1/2}\] but not sure where to go from there

OpenStudy (lgbasallote):

oh wait..it's 2?? i thought it was 3

OpenStudy (anonymous):

yes, its 2 :)

OpenStudy (lgbasallote):

\[\large \ln (\sqrt[4]{ab^2}) = \ln (ab^2)^{1/4}\] power rule \[\large \frac 14 \ln (ab^2)\] multiplication law \[\frac14 \ln a + \frac 14 \ln b^2\] power rule again \[\frac 14 \ln a + \frac 24 \ln b\] simplify \[\frac 14 \ln a + \frac 12 \ln b\] do you get that?

OpenStudy (anonymous):

yes that is what i got

OpenStudy (anonymous):

now, is there any more simplifying?

OpenStudy (lgbasallote):

nope

OpenStudy (anonymous):

ahh ok, i made it more complicated than it was. for some reason i was trying to cancel out ln to simplify

OpenStudy (lgbasallote):

haha lol =))) your question was requiring sum of logarithms why cancel haha

OpenStudy (anonymous):

yes, correct. lol thank you, may i ask another question?

OpenStudy (lgbasallote):

sure shoot

OpenStudy (anonymous):

ok i must graph this function: f(x)=log(x+1). I have worked out other similar functions where there is a number for the base. for example: \[\log _{2}(x+1)\]. I also know that log(x) is 10 but not sure if that is my base when using\[x=a^{y}\]

OpenStudy (lgbasallote):

aww graphing :/ im weak in graphing

OpenStudy (anonymous):

ok, lol. I actually have plugged in numbers and checked the graph, although the coordinates look a bit off and im just not certain they are correct.

OpenStudy (anonymous):

would you know how to change log(x+1) into the \[x=a^{y}\] form?

OpenStudy (lgbasallote):

yep... \(\log (x+1)\) has a base 10 so it's just like \(\log_{10} (x+1)\) remember that if you see log and there's no base then it's automatic that it's 10

OpenStudy (anonymous):

yes, i thought so. Just want sure. Ok so then it would be \[(x+1)=10^{y}\] correct?

OpenStudy (lgbasallote):

if it was \[\log (x+1) = y\] then yes

OpenStudy (anonymous):

thank you very much!!!

OpenStudy (lgbasallote):

<tips hat>

OpenStudy (anonymous):

:D

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