Question

h(x)=(x-2)/(-8-3x) what is the inverse?

Answer 1

so (-8-3x)/(x-2)?

Answer 2

i thought inverse meant \(h^{-1} (x)?\)

Answer 3

yea

Answer 4

you swap \(x\) and \(y\)

Answer 5

yeah, not recipicle:)

Answer 6

swap x and y and solve for y

Answer 7

Oh @eyad said it was the reciprocal.

Answer 8

Then..
\[x=\frac{y-2}{-8-3y} \]
solve for \(y\)

Answer 9

I got that far. So x(-8-3y)=y-2