Question

Can someone please show me how to answer this quadratic equation?
Attachment Below

Answer 1

what's the big deal?
see where y is positive or negative (acc. to condition)
and then for which x it is so it is ur answer.

Answer 2

... I don't understand that. This is my first time learning about sketch graphs. @mayank_mak

Answer 3

seeing the graph tell me for what x is y positive?

Answer 4

where am I looking for y...?@mayank_mak

Answer 5

(x+1)(x-3)>0

x<-1 , x>3

Answer 6

by convention y axis is vertical and x axis is horizontal

upper half of y axis is +ve
lower half of y-axis is -ve
right half of x-axis is +ve
left half of x- axis is -ve (these all are by convention)

Answer 7

1. (x +1)(x - 3) > 0
x >-1 and x > 3

-1 < x > 3


2. -x2 + 5x -6 >= 0
x2 - 5x + 6 >= 0
x2 -3x -2x + 6 >=0
x(x-3) -2 (x -3) >=0
(x - 3) (x - 2) >=0

x >= 3 and x>=2..

Answer 8

\[-x^2+5x-6\ge 0\]
\[(-x+2)(x-3)\ge0\]
\[ 2 \le x \le3 \]