Question

multiply. simplify answer as much as possible.

(x-3)/(4x+12) * (x^2+x-6)/(x^2-4x+3)

Answer 1

\[
\frac{(x-3)
\left(x^2+x-6\right)}{(4
x+12) \left(x^2-4
x+3\right)}
\]
Is this your problem to be simplified?

Answer 2

yes

Answer 3

\[
\frac{(x-3)
\left(x^2+x-6\right)}{(4
x+12) \left(x^2-4
x+3\right)}=\frac{(x-3)
(x-2) (x+3)}{4 (x+3) (x-3)
(x-1)}
\]
Can you finish it now?

Answer 4

no i still need help

Answer 5

Cancel what is common up and down.

Answer 6

\[
\frac{(x-3)
\left(x^2+x-6\right)}{(4
x+12) \left(x^2-4
x+3\right)}=\frac{(x-3)
(x-2) (x+3)}{4 (x+3) (x-3)
(x-1)}=\frac{x-2}{4
(x-1)}
\]

Answer 7

Did you understand it?