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multiply. simplify answer as much as possible. (x-3)/(4x+12) * (x^2+x-6)/(x^2-4x+3)
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\[ \frac{(x-3) \left(x^2+x-6\right)}{(4 x+12) \left(x^2-4 x+3\right)} \] Is this your problem to be simplified?
yes
\[ \frac{(x-3) \left(x^2+x-6\right)}{(4 x+12) \left(x^2-4 x+3\right)}=\frac{(x-3) (x-2) (x+3)}{4 (x+3) (x-3) (x-1)} \] Can you finish it now?
no i still need help
Cancel what is common up and down.
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\[ \frac{(x-3) \left(x^2+x-6\right)}{(4 x+12) \left(x^2-4 x+3\right)}=\frac{(x-3) (x-2) (x+3)}{4 (x+3) (x-3) (x-1)}=\frac{x-2}{4 (x-1)} \]
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